{\large \begin{array}{l}geg.:\,\,d=0,42\,m\,\,\,\,\,\,\,\,\,\,\,\,ges.:\,F\\\,\,\,\,\,\,\,\,\,\,\,\,\,{{p}_{0}}\,=\,101\,kPa\end{array} }
Zunächst berechnen wir die Kreisfläche der Halbkugel.
{\large\begin{array}{l}{{A}_{\,Kreis}}\,=\,\frac{\pi }{4}{{d}^{2}}\\\\{{A}_{\,Kreis}}\,=\,\frac{\pi }{4}\cdot {{0,42}^{2}}\,{{m}^{2}}\\\\{{A}_{\,Kreis}}\,=\,0,14\,{{m}^{2}}\end{array} }
{\large\begin{array}{l}F\,=\,p\cdot \,A\\F\,=\,101\,kPa\,\cdot \,0,14\,{{m}^{2}}\\F\,=\,101\,000\,\frac{N}{{{m}^{2}}}\,\cdot \,0,14\,{{m}^{2}}\\\\F\,=\,14140\,N\,\approx \,14\,kN\end{array} }